Nitrogen flow calculation

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1. Conversion of Ar gas and N2 flow rate

1ar flow rate=1.4n2 flow rate. According to the ratio of the molecular weight of two gases, argon (Ar) and nitrogen (N2), the molecular weight of argon is 17.2, while the molecular weight of nitrogen is 28.02. Therefore, a flow rate of 1 Ar is equivalent to 1.4 times the flow rate of nitrogen.

2. The flow rate of 2mpa nitrogen per hour in DN10 pipeline

For the flow calculation of DN10 pipeline under 2MPa nitrogen pressure, the theoretical flow rate per hour is about 2.8 cubic meters, but it will be significantly affected by other factors in actual working conditions.

1. Basic Condition Setting: The following assumptions are usually assumed by default when calculating:

1. The pipeline is a straight section without valves, elbows, etc., and only includes local resistance elements such as sails.

2. Core calculation steps 1 When calculating the inner diameter d=0.01m for pipeline cross-sectional area: A=π× (0.01/2) ² ≈ 7.85 × 10 ⁻⁵ m ² 5.65m ³/h

III. Influence of Core Variables: When the following parameters change, the flow rate of the mountain fluid will experience nonlinear fluctuations: • When the pipe length increases by 1 time, the flow rate will decrease by about 29-35% • Two 90 ° elbows appear, which is equivalent to an increase of 0.6-0.8 times the equivalent pipe length • When the temperature rises to 50 ℃, the flow rate will increase by ab

IV. Engineering reference parameters refer to GB50235 Industrial Pipeline Specification, The nitrogen flow rate of DN10 pipes under different pressure differentials: | pressure differential (MPa) | reference flow rate (m ³/h) | | -------------------------------------------------------------------------------------------. The numerical range in the table confirms the feasibility of theoretical calculations and intuitively reflects the flow fluctuation space under different operating conditions.

3... How much flow of N2 (nitrogen) can be transported at a pressure of 0.4MPa? Under standard conditions, thank you very much! _Hundred The key to your question is to determine the flow rate of nitrogen, and the square of the flow rate is proportional to the pipeline resistance and the length of the pipeline. In industry, there is generally a limit value that allows pipeline resistance, and there is also a problem of optimal design, which considers the minimum value of power consumption and investment. However, in industry, for small projects, the economic flow rate obtained from experience is generally taken. Gas is generally taken as 20-40m/s. If 30m/s is taken, the gas flow rate is 30 × 0.025 × 0.025 × 3.14 ÷ 4 × 3600=53 (cubic meters/hour). (Assuming the inner diameter of the pipeline is 25, 0.4MPa is the gauge pressure, and the temperature is 0 ℃, the gas volume in the standard state of circular liquid can be calculated as 53 × 5 ÷ 1=265 standard cubic meters/hour.). You can also convert it to 265 ÷ 22.4 × 14=165.6 (kg/h)

4. Is the gas mass flowmeter easy to use?

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